1.

If x = 1; y = 2 find the values of the following expressions(i) 4x – 3y + 5(ii) x2 + y2(iii) xy + 3y – 9

Answer»

i) 4x – 3y+5

If x = 1, y = 2 then the value of 4x – 3y + 5 

= 4(1) – 3(2) + 5

= 4 – 6 + 5

= 9 – 6 = 3

ii) x2 + y2

If x = 1, y = 2, the value of x2 + y2= (1)2 + (2)2
=(1 × 1) + (2 × 2)
= 5

iii) xy + 3y – 9

If x = 1; y = 2,the value of xy + 3y – 9 

= 1 × 2 + 3(2) – 9

= 2 + 6 – 9

= 8 – 9



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