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If x = 1; y = 2 find the values of the following expressions(i) 4x – 3y + 5(ii) x2 + y2(iii) xy + 3y – 9 |
Answer» i) 4x – 3y+5 If x = 1, y = 2 then the value of 4x – 3y + 5 = 4(1) – 3(2) + 5 = 4 – 6 + 5 = 9 – 6 = 3 ii) x2 + y2 If x = 1, y = 2, the value of x2 + y2= (1)2 + (2)2 iii) xy + 3y – 9 If x = 1; y = 2,the value of xy + 3y – 9 = 1 × 2 + 3(2) – 9 = 2 + 6 – 9 = 8 – 9 |
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