If x√1+y+y√1+x=0, for −1<x<1, prove that dydx=−1(1+x)2 – InterviewSolution

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1.	If x√1+y+y√1+x=0, for −1<x<1, prove that dydx=−1(1+x)2
Answer» $I f x \sqrt{1 + y} + y \sqrt{1 + x} = 0, f o r - 1 < x < 1, p r o v e t h a t \frac{d y}{d x} = - \frac{1}{(1 + x)^{2}}$

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