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If x^2-2px+q=0 has two equal roots then the equation (1+y)x^2 -2(p+y)x +(q+y)=0 will have real and distinct roots when

Answer» If x^2-2px+q=0 has two equal roots then the equation (1+y)x^2 -2(p+y)x +(q+y)=0 will have real and distinct roots when


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