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If x=2/3 and x= -3 are the roots of quadratic equation ax+7x+b=O.find the value of a and b.

Answer» {tex}ax^2+7x+b=0{/tex}let the roots are p and qp+q=-7/a=2/3+(-3)=2/3 - 9/3= -7/3or -7/a= -7/3hence -7a=-21 so a= 3also{tex}\\begin{array}{l}pq=\\frac ba=\\frac23\\times(-3)=-2\\\\but\\;a=\\;3\\\\so\\;\\;\\frac b3=-2\\\\so\\;b=3\\times-2=-6\\;and\\;a=3\\end{array}{/tex}\xa0


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