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If `x^(2) + ax+ b` and `x^(2) + bx + c` have a common factor `(x-k)`, then `k ="_____"`.A. `(a-b)/(b-c)`B. `(b-c)/(c-a)`C. `(c-b)/(b-a)`D. `(c-b)/(a-b)` |
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Answer» Correct Answer - D `x^(2) + ax + b` and `x^(2) + bx + c` have a common factor `(x-k)`. `rArr k^(2) + ak + b = 0` and `k^(2) + bk + c= 0` `rArr k^(2) + akl + b = k^(2) + bk + c` `ak + b = bk + c` `k = (c-b)/(a-b)`. |
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