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If (x – 2) is a factor of x3– mx2 + 10x – 20, then find the value of . |
Answer» p(x) = x3 – mx2 + 10x – 20 x – 2 is a factor of x3 – mx2 + 10x – 20. ∴By factor theorem, Remainder = p(2) = 0 p(x) = x3 – mx2 + 10x – 20 ∴ p(2) = (2)3– m(2)2 + 10(2) – 20 ∴ 0 = 8 – 4m + 20 – 20 ∴ 0 = 8 – 4m ∴ 4m = 8 ∴ m = 2 |
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