If x = \(2^{sin^2θ}\) , y = \(2^{cos^2θ}\) for all real values of θ, then (1) x + y = 1(2) x + y = 2(3) x + y ≤2 √2(4) x + y ≥ 2 √2

If x = \(2^{sin^2θ}\) , y = \(2^{cos^2θ}\) for all real values of

1.	If x = \(2^{sin^2θ}\) , y = \(2^{cos^2θ}\) for all real values of θ, then (1) x + y = 1(2) x + y = 2(3) x + y ≤2 √2(4) x + y ≥ 2 √2
Answer» Correct option is (4) x + y ≥ 2 √2

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If x = \(2^{sin^2θ}\) , y = \(2^{cos^2θ}\) for all real values of θ, then (1) x + y = 1(2) x + y = 2(3) x + y ≤2 √2(4) x + y ≥ 2 √2

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