1.

If x^(2) + x + y^(2) - 1 = 0, where x > 0 and y > 0 then maximum value of xsqrt(y) is

Answer»

`1/(3sqrt2)`
`1/(2SQRT2)`
`sqrt(2)`
`2sqrt(2)`

SOLUTION :`x^(2) + x = 1 - y^(2) x, y > 0`
`(x^(2) + x/2 + x/2 + y^(2))/(4) GE ((x^4 y^2)/4)^(1//4`
`1/4 ge (xsqrt(y))/(sqrt(2)) implies xsqrt(y) implies xsqrt(y) le 1/(2sqrt2)`.


Discussion

No Comment Found

Related InterviewSolutions