1.

If x=-2 , y=6 is a solution of equation 3ax+2ay=6 then find value of \'b\' from 2(a-1)+2(3b-4)=4.

Answer» Given, x = -2 and y = 63ax+2ay=63a(-2) + 2a(6)=6-6a+12a=66a=6a=6/6=1=>2(a-1)+2(3b-4)=42(1-1)+2(3b-4)=40+(3b-4)=4/23b=2+4b=6/3=2
3a(2)+2a(6)=66a+12a=618a=6a=32(3-1)+2(3b-4)=42(2)+6b-8=44-8+6b=4-4+6b=46b=4+46b=8b=8÷6b=1.3
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