if x=2k+1andy=I is a solution of the equation 5x+3y-7=0 by substitutin – InterviewSolution

1.

if x=2k+1andy=I is a solution of the equation 5x+3y-7=0 by substituting the value of candy in equation we get

Answer»

x = 2k + 1 y = k is the solution of 5x + 3y - 7 = 0 5(2k+1)+3k - 7 = 0 10k + 5 + 3k - 7 = 0 13k - 2 = 0 13k = 2 k = 2/13

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