If (x-3) is a factor of p(x)=xcube-kxsquare+(k+1)x-12,find the value o

1.	If (x-3) is a factor of p(x)=xcube-kxsquare+(k+1)x-12,find the value of k?
Answer» Niharika yadav you wrote the wrong answere K=3 p(x) = x3 - kx2 + (k + 1)x - 12x - 3 is a factor So, put x = 333 - k(3)2 + (k +1)3- 12 = 027 - 9k +3k + 3 - 12 = 0-6k + 18 = 0-6k = -18k = 18/6k =3\xa0 K equals to minus 2

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