If x = 3 is one root of the quadratic equation x2 -2kx - 6 = 0, then

1.	If x = 3 is one root of the quadratic equation x2 -2kx - 6 = 0, then find the value of k.
Answer» Let p(x)=x²-2kx-6=0 x = 3 is one root of the quadratic equation So, Remainder = p(3) = 0 p(3) =0 (3)²-2k(3)-6=0 -6k=-3 So, k=3/6=1/2 so, k=1/2

If x = 3 is one root of the quadratic equation x2 -2kx - 6 = 0, then find the value of k.

Answer»

Let p(x)=x²-2kx-6=0

x = 3 is one root of the quadratic equation

So, Remainder = p(3) = 0

p(3) =0

(3)²-2k(3)-6=0

-6k=-3

So, k=3/6=1/2

so, k=1/2

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If x = 3 is one root of the quadratic equation x2 -2kx - 6 = 0, then find the value of k.

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