If x = 4 is a zero of the polynomial 2x2 + kx - 12, then find the valu

1.	If x = 4 is a zero of the polynomial 2x2 + kx - 12, then find the value of k.
Answer» P(x)= 2x²+kx-12 P(4)=2(4)²+k(4)-12P(4)=2(16)+k*4-12P(4)=32+4k-12p(4)=-20+4kNow we have to find k;k=-20/4k=-5HENCE,k=-5 P(x) = 2x² + kx - 12 P(4) = 2(4)² + k(4) - 12 0 = 32 + 4k - 12 0 = 20 + 4k -20 = 4k k = -20/4 k= -5 P(x) = 2x² + kx - 12P(4) = 2(4)² + k(4) - 120 = 32 + 4k - 120 = 20 + 4k-20 = 4kk = -20/4k= -5

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