1.

If x=8 ,find the value of x²+x-5

Answer» Given :x=8x²+x-5(8)² + 8-564+8-572-567
67
Sorry by-mistake added x = 6 in place of x= 8.
Let p(x)=x^2 +x-5Putting x=8 in p(x) = (8)^2+8-5= 64+8-5= 64+3 = 67
Put x = 8x²+x-5= (6)2 + 6 - 5= 36 + 1= 37\xa0\xa0


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