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If x = a cos θ, y = b sin θ, then find dy/dx. |
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Answer» According to question, x = a cos θ ...(i) y = b sin θ...(ii) Equation (i) differentiating w.r.t., θ dx/dθ = ad cosθ/dθ = a x (-sin θ) = -a sin θ Then eq. (ii) differentiating w.r.t θ dy/dθ = bd sinθ/dθ = b cosθ Hence, dy/dx = dy/dθ/dx/dθ = b cosθ/-a sinθ = (b/-a) cot θ |
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