If x=(a sin theta+b cos theta )/(a+b), then

1.	If x=(a sin theta+b cos theta )/(a+b), then
Answer» the dimensions of `x` and `a` are same the dimensions of `a` and `B` are not same `x` is dimensions None of the above Solution :(C) `x=(a sin theta + b cos theta)/(a+b)` `:.[x]=[(a sin theta)/(a+b)]=[(b cos theta)/(a+b)]` or `[x]=` DIMENSIONLESS

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