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If [x] and {x} represents integral and fractional parts of a real number x, and f(x) = (a^(2[x] +{x})-1)/(2[x} + {x}), x ne 0, f(0) = log_(e) a, where a gt 0, a ne 1, then |
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Answer» `f(X)` is continous at x=0 |
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