If x and y are directly proportional, find the value of x1, x2 and y2

1.	If x and y are directly proportional, find the value of x1, x2 and y2 in the table given below:X3x1x210Y72120192y2
Answer» We use the relation \(\frac{\text{x}}{y}=\frac{\text{x}}{y}\) Here x₁ = 5, y₁ = 210 and x₂ = 2 Here, \(\frac{3}{72}=\frac{\text{x}{_1}}{120}\) ⇒ x₁ × 72 = 3 × 120 ⇒ x₁ = \(\frac{3\,\times\,120}{72}=5\) Now, \(\frac{3}{72}=\frac{\text{x}{_2}}{192}\) ⇒ x₂ × 72 = 3 × 192 ⇒ x₂ = \(\frac{3\,\times\,192}{72}=8\) And \(\frac{3}{72}=\frac{10}{y{_2}}\) ⇒ y₂ × 3 = 10 × 72 ⇒ y₂ = \(\frac{10\,\times\,72}{3}=240\)

If x and y are directly proportional, find the value of x1, x2 and y2 in the table given below:X3x1x210Y72120192y2

Answer»

We use the relation \(\frac{\text{x}}{y}=\frac{\text{x}}{y}\) Here x₁ = 5, y₁ = 210 and x₂ = 2

Here, \(\frac{3}{72}=\frac{\text{x}{_1}}{120}\)

⇒ x₁ × 72 = 3 × 120

⇒ x₁ = \(\frac{3\,\times\,120}{72}=5\)

Now, \(\frac{3}{72}=\frac{\text{x}{_2}}{192}\)

⇒ x₂ × 72 = 3 × 192

⇒ x₂ = \(\frac{3\,\times\,192}{72}=8\)

And \(\frac{3}{72}=\frac{10}{y{_2}}\)

⇒ y₂ × 3 = 10 × 72

⇒ y₂ = \(\frac{10\,\times\,72}{3}=240\)