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If X and Y are the two digits of the number 347XY such that the number is completely divisible by 80, then what is the value of X + Y?1). 22). 43). 64). 8 |
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Answer» For any number to be completely divisible by 80, it must be divisible by 8 and 10 both So, for the number 347XY to be divisible by 10 the LAST digit must be a 0 This means, Y = 0 and also for any number to be divisible by 8 the last three digits of the number must be divisible by 8. When 347X0/(10 × 8) THUS gives 347X divides exactly by 8 So, the last three digits ie 47X must be divisible by 8 This means X = 2 is the only possible value ∴ X + Y = 2 + 0 = 2 |
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