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if x and y be two non zero vectors such that |x+y|=|x-2y| then prove that least value of (x.y)+(1/(|y|^2+2)) is (√2)-1

Answer» if x and y be two non zero vectors such that |x+y|=|x-2y| then prove that least value of (x.y)+(1/(|y|^2+2)) is (√2)-1


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