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If x = \(\cfrac{√ 3- √ 2}{√ 3+√ 2},y\,=\cfrac{√ 3+√ 2}{√ 3-√ 2}\) , then the value of x2 + xy + y2 is(1) 49 (2) 78 (3) 98 (4) 99 |
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Answer» Correct option is (4) 99 |
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