1.

If `(x)/(cos theta)=(y)/(cos(theta-(2pi)/(3)))=(z)/(cos(theta+(2pi)/(3))), then x+y+z=`A. 1B. 0C. `-1`D. none of these.

Answer» Correct Answer - B
We have
`(x)/(cos theta)=(y)/(cos(theta-(2pi)/(3)))=(1)/(cos(theta+(2pi)/(3)))`
Therefore each ratio is equal to
`(x+y+z)/(cos theta+cos(theta-(2pi)/(3)))=(x)/(cos(theta+(2pi)/(3)))=(x+y+z)/(0)`
or `x+y+z=0`


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