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In a triangle `tan A+ tan B + tan C=6` and `tan A tan B= 2,` then the values of `tan A, tan B` and `tan C` areA. 1,2,3B. `3,2//3,7//3`C. `4,1//2,3//2`D. none of these. |
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Answer» Correct Answer - A In triangle. `tanA+tanB+tanC=tanA tan B tan C` `rARr 6=2tanC` or `tanC=3` Also `an A+tanB=6-3=3` By Eqs. I and ii, `tanA` and `tanB` are roots of `x^(2)-3x+2=0`. thus, `tanA,tanB=2,1` or `2,2` and `tanC=3`. |
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