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If x=cosec θ−sinθ,y=cosecnθ−sinnθ,n∈R then (x2+4)(dydx)2−n2y2= |
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Answer» If x=cosec θ−sinθ,y=cosecnθ−sinnθ,n∈R then (x2+4)(dydx)2−n2y2= |
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