1.

If x=eθ(sinθ+cosθ) and y=eθ(sinθ –cosθ), where θ is a real parameter, then d2ydx2 at θ=π6 is

Answer»

If x=eθ(sinθ+cosθ) and y=eθ(sinθ cosθ), where θ is a real parameter, then d2ydx2 at θ=π6 is



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