If x = ex/y, prove that dy/dx = (x - y)/x log y

1.	If x = ex/y, prove that dy/dx = (x - y)/x log y
Answer» x = e^x/y log x = log e^x/y = (x/y) log e y log x = x Differentiating both sides w.r.t. x dy/dx = (x - y)/x log y

Answer»

x = e^x/y

log x = log e^x/y = (x/y) log e

y log x = x

Differentiating both sides w.r.t. x

dy/dx = (x - y)/x log y

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If x = ex/y, prove that dy/dx = (x - y)/x log y

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