1.

If x g is the mass of NaHC_(2)O_(4) required to neutralize 100 ml of 0.2 M NaOH and y g that requiredto reduce 100 ml of 0.02 M KMnO_(4)in acidic medium then

Answer»

`x=y`
`2x=y`
`x=4y`
`4x=y`

Solution :`NaHC_(2)O_(4)` Vs NaOH is ACID base titration
EQ. of `NaHCl_(2)O_(4)` = Eq. of NaOH
`(x)/(M)=(100xx0.2xx1)/(1000)...(1)`
`NaHCl_(2)O_(4)` Vs `KMnO_(4)` is redox titration
Eq. `NaHC_(2)O_(4)` = Eq. of `KMnO_(4)`
`(y)/(M//2)=(100xx0.02xx5)/(1000)....(2)`
from Eq. (1) % (2) = 1 `x=4y`


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