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If x g is the mass of NaHC_(2)O_(4) required to neutralize 100 ml of 0.2 M NaOH and y g that requiredto reduce 100 ml of 0.02 M KMnO_(4)in acidic medium then |
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Answer» `x=y` EQ. of `NaHCl_(2)O_(4)` = Eq. of NaOH `(x)/(M)=(100xx0.2xx1)/(1000)...(1)` `NaHCl_(2)O_(4)` Vs `KMnO_(4)` is redox titration Eq. `NaHC_(2)O_(4)` = Eq. of `KMnO_(4)` `(y)/(M//2)=(100xx0.02xx5)/(1000)....(2)` from Eq. (1) % (2) = 1 `x=4y` |
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