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If `x_i>0` i=1,2,3,...50 `x_1+x_2...+x_50=50` then the minimum value of `1/(x_1) +1/(x_2) +...+1/(x_50)` equals |
Answer» AM`>=GM>=HM` `1/x_1*1/x_2*1/x_3...1/x_50` `(1/x_1+1/x_2+1/x_3...1/x_50)/50>=(1/(x_1+x_2+x_3...x+50))/50` `1/x_1+1/x_2+1/x_3+...+1/x_50>=50`. |
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