1.

If x is the fraction of PCI5 dissociated at equilibrium in the reaction,PCl5 ⇌ PCl3 + Cl2 Then starting with 0.5 moIe of PCI5 the total number of moles of reactants and products at equilibrium is(a) 0.5 – x (b) x + 0.5 (c) 2x + 0.5 (d) x ± 1

Answer»

(b) x + 0.5

PCl5PCl3Cl2
Initial no. of moles0.5--
No. of moles dissociated and formedx--
No. of moles at equilibrium0.5 - xxx

Total no. of moles at equilibrium = 0.5 – x + x + x 

= 0.5 + x


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