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If (x + k) is the HCF of ax2 + ax + b and x2 + cx + d, then what is the value of k ?(a) \(\frac{b+d}{a+c}\) (b) \(\frac{a+b}{c+d}\)(c) \(\frac{a-b}{c-d}\)(d) None of these |
Answer» (d) None of these Hint. ak2 – ak + b = 0 k2 – ck + d = 0 Solving by the rule of cross multiplication, \(\frac{k^2}{-ad+bc}\) = \(\frac{k}{b-ad}\) = \(\frac{1}{-ac+a}\) ⇒ k = \(\frac{b-ad}{a(1-c)},\frac{bc-ad}{b-ad}.\) |
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