Saved Bookmarks
| 1. |
If x lies in the interval [0, 1], then the least value of x2 + x + 1 is :A. 3 B. \(\frac{3}{4}\)C. 1 D. none of these |
|
Answer» Option : (C) f(x) = x2 + x + 1 f’(x) = 2x + 1 f’(x) = 0 ⇒ 2x + 1 = 0 ⇒ x = -\(\frac{1}{2}\) At extreme points, f(0) = 0 f(1) = 1 + 1 + 1 > 0 So, x = 1 is a least value. |
|