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If `x^(p) y^(q) = (x + y)^((p + q)) " then " (dy)/(dx)=` ?A. `y//x`B. `py//qx`C. `x//y`D. `qy//px` |
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Answer» Correct Answer - A Given, `x^(p)y^(q)=(x+y)^(p+q)` Thinking log on both sides, we get `p log x+q log y=(p+q)log (x+y)` `implies(p)/(x)+(q)/(y)(dy)/(dx)=((p+q))/((x+y))(1+(dy)/(dx))` `implies((p)/(x)-(p+q)/(x+y))=((p+q)/(x+y)-(q)/(y))(dy)/(dx)` `implies(dy)/(dx)=y/x` |
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