1.

If x = sec theta - cos theta and y = sec^(n) theta - cos^(n) theta then ((dy)/(dx))^2 is equal to

Answer»

`(n^2(y^2+4))/(X^2+4)`
`(n^2(y^2-4))/(x^2)`
`(n^2(y^2-4))/(x^2-4)`
`((NY)/x)^2-4`

ANSWER :A


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