1.

If x= sec theta - cos theta, y = sec' theta - cos'' theta, then (dy)/(dx) =

Answer»

`sqrt((y^(2) + 4)/(X^(2) + 4))`
`n sqrt((y^(2) + 4)/(x^(2) + 4))`
`sqrt((x^(2) + 4)/(y^(2) + 4))`
`n sqrt((x^(2) + 4)/(y^(2) + 4))`

ANSWER :B


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