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If `x=(sqrt(p^6+q^2)+sqrt(p^2-q^2))/(sqrt(p^2+q^2)-sqrt(p^2-q^2))` then `q^2x^2-2p^2x+q^2=?` |
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Answer» `x = (sqrt(p^2+ q^2) + sqrt(p^2 - q^2))/(sqrt (p^2 + q^2) - sqrt(p^2 - q^2))` multiply by `sqrt(p^2 + q^2) + sqrt(p^2 - q^2)` `x = ((sqrt(p^2 + q^2) + sqrt(p^2 - q^2))^2)/(sqrt(p^2 + q^2) - sqrt(p^2 - q^2))` `= (p^2 + q^2 + p^2 - q^2 + 2 sqrt((p^2+ q^2)(p^2- q^2)))/(p^2 + q^2 - p^2 + q^2)` `x = (p^2 + sqrt(p^4 - q^4))/q^2` `x^2 = (p^4 + p^4 - q^4 + 2 p^2 sqrt(p^4 - q^4))/q^4` `= (2p^4 - q^4 + 2p^2 sqrt(p^4 - q^4))/q^2 - (2p^4 - 2p^2 sqrt(p^4 - q^4))/q^2 + q^2` `= -q^4/q^2 + q^2 = 0` here, `p=1, q=1` `x = (sqrt2 - 0)/(sqrt2 - 0) = 1` `q^2x^2 - 2p^2x + q^2` `1 xx 1 - 2 + 1 = 0` answer |
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