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If `x-x^2/2+x^3/3+x^4/4+.....` to `oo=y` , then `y+y^2/(2!)+y^3/(3!)+....` + to `oo` is equal toA. `e^(y)-1`B. `log_(e)(1+y)`C. `x^(3)=e^(y)`D. `x=1+e^(y)` |
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Answer» Answer: We have `y=x-(x^(2))/(2)+(x^(3))/(3)-(x^(4))/(4)`+.. `rarr y= log_(e)(1+x)rarre^(y)=1+xrarrx=e^(y)-1` |
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