1.

If x + y = 12 and xy = 27, find the value of x3 + y3 .

Answer»

x3 + y3 

= (x + y) (x2 – xy + y2

= (x + y) [(x + y)2 – 3xy]

= 12 [122 – 3 × 27] 

= 12 × 63 

= 756



Discussion

No Comment Found