If x/y + y/x=-1( where x,y is not equal to 0) then find the value of xcube - ycube

If x/y + y/x=-1( where x,y is not equal to 0) then find the value of x

1.	If x/y + y/x=-1( where x,y is not equal to 0) then find the value of xcube - ycube
Answer» \xa0We know that,x3\xa0- y3\xa0= (x - y)(x² + xy + y²) ....(i)Given that, x/y + y/x = -1(x² + y²)/xy = -1x² + y² = -xyx² + y² + xy = 0(x² + xy + y²) = 0Multyplying by (x - y) on both sides we get,(x - y)(x² + xy + y²) = (x - y) × 0x3\xa0- y3\xa0= 0 using (i)