InterviewSolution
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InterviewSolution
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If `x+y+z=0` show that `x^3+y^3+z^3=3x y z`. |
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Answer» We have this formula, `x^3 + y^3 +z^3 - 3xyz = (x+y+z)(x^2+y^2+z^2-xy-yz-zx)` Here, we are given, `x+y+z = 0`, So,our formula becomes `x^3 + y^3 +z^3 - 3xyz =0**(x^2+y^2+z^2-xy-yz-zx)` `x^3 + y^3 +z^3 - 3xyz =0` `x^3 + y^3 +z^3 = 3xyz ` |
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