If x+y+z = 0 ,show that x(cube) + y(cube) + z(cube) = 3xyz

1.	If x+y+z = 0 ,show that x(cube) + y(cube) + z(cube) = 3xyz
Answer» When x+y+z=0 then,x(cube)+y(cube)+z(cube)-3xyz=0 Or x cube + y cube + Z cube=0+3xyz Therefore, x cube + y cube + Z cube=3xyz Hence proved

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