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If x + y + z = 0, show that x3 + y3 + z3 = 3xyz. |
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Answer» x + y + z = 0 x + y = -z by cubing on both sides, (x + y)3 = (-z)3 x3+ y3 + 3xy(x + y) = -z3 x3 + y3 + 3xy (-z) = -z (∵ x + y =-z data given) x3 + y3 – 3xyz = -z3 ∴ x3 + y3 + z3 = 3xyz. |
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