If x+y+z=0 then prove that x^3+y^3+z^3 = 3xyz

1.	If x+y+z=0 then prove that x^3+y^3+z^3 = 3xyz
Answer» x+y=-z ....equ.1(x+y)³=(-z)³ (Cube of both sides)X³+y³+3xy(x+y)=-z³x³+y³+3xy(-z)=-z³ (Using equ.1)x³+y³-3xyz =-z³x³+y³+z³ =3xyzHence, it is proved. When u posted this

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