If x+y+z=0, then show that x^2+y^2+z^2=-2(xy+yz+zx)

1.	If x+y+z=0, then show that x^2+y^2+z^2=-2(xy+yz+zx)
Answer» Channel name :(The royal star vines) Desi boyz Video name : the story of a Desi boy Please subscribe and like on YouTube plz plz plz plz plz plz plz plz plz plz plz plz (x+y+z)²=0²x²+y²+z²+2xy+2yz+2zx=0transpose 2xy+2yz+2zx to RHSx²+y²+z²= -(2xy+2yz+2zx)Take 2 commonx²+y²+z²=-2(xy+yz+zx)

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