1.

If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is(a) an odd multiple of 3 (b) odd multiple of 6(c) even multiple of 3 (d) even multiple of 9

Answer»

The correct answer is option (a) an odd multiple of 3

Explanation:

Given that, the sum of the digits xyz is given as x+y+z is 6, where z is an odd integer.

The divisibility test of 3, the number xyz is divisible by z. Since the last digit is an odd digit, then xyz is an odd multiple of 3.



Discussion

No Comment Found