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If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is(a) an odd multiple of 3 (b) odd multiple of 6(c) even multiple of 3 (d) even multiple of 9 |
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Answer» The correct answer is option (a) an odd multiple of 3 Explanation: Given that, the sum of the digits xyz is given as x+y+z is 6, where z is an odd integer. The divisibility test of 3, the number xyz is divisible by z. Since the last digit is an odd digit, then xyz is an odd multiple of 3. |
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