1.

If x, y, z are different from zero and 1+x1111+y1111+z=0, then the value of x−1 + y−1 + z−1 is(a) xyz(b) x−1 y−1 z−1(c) − x − y − z(d) − 1

Answer» If x, y, z are different from zero and 1+x1111+y1111+z=0, then the value of x−1 + y1 + z1 is



(a) xyz

(b) x−1 y1 z1

(c) − x − y − z

(d) − 1


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