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If x, y, z are different from zero and 1+x1111+y1111+z=0, then the value of x−1 + y−1 + z−1 is(a) xyz(b) x−1 y−1 z−1(c) − x − y − z(d) − 1 |
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Answer» If x, y, z are different from zero and , then the value of x−1 + y−1 + z−1 is (a) xyz (b) x−1 y−1 z−1 (c) − x − y − z (d) − 1 |
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