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If x,y,z are integers and x ≥ 0 , y ≥ 1, z ≥ 2 and x + y + z = 15, then the number of ordered triplets (x,y,z) is (a) 91 (b) 455 (c) 17C2 (d) none of these |
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Answer» Correct option (a) 91 Explanation: x ≥ 0, y ≥ 1, z ≥ 2 and x + y + z = 15 we can say 12 objects (alike) are to be distributed among 3 persons. (distribution of alike objects) Apply n+r–1Cr–1 when n = 12, r = 3 12+3–1C3–1 = 14C2 = 2 14 x 13/2 = 91 |
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