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If `x^yxxy^x=256`,then find `y^2-x^2` where x and y are positive integers and `x lt y`).A. 15B. 12C. 14D. 16 |
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Answer» Correct Answer - B `x^yxxy^x=256=16xx16=2^4xx4^2` `rArr x^yxxy^x=2^4xx4^2` `rArr x=2` and `y=4 (becauase x lt y)` `therefore y^2=x^2=16 -4=12` Hence, the correct option is (b). |
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