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If `x^yxxy^x=800`, then find `x-y` (where x and y are positive integers and `xgt y`).A. 2B. 5C. 4D. 3 |
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Answer» Correct Answer - D `x^yxxy^x=800` `rArr x^y xx y^x=25xx32` `rArr 5^2xx2^5=x^yxxy^x(because x gt y)` `rArrx-y=5-2=3` Hence the correct option is (d). |
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