InterviewSolution
x ∈ Z1 < 3x + 5 ≤ 11⇒ 1 < 3x + 5⇒ 1 – 5 < 3x⇒ –4 < 3x⇒ -4/3 < xand3 + 5 ≤ 11⇒ 3x ≤ 11 – 5⇒ 3x ≤ 6⇒ x ≤ 6/3⇒ x ≤ 2∴ -4/3 < x ≤ 2Solution set = {–1, 0, 1, 2}.
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