If x2−1=−b2−2bx and x2−1=−a2−2ax have exactly one root in – InterviewSolution

1.	If x2−1=−b2−2bx and x2−1=−a2−2ax have exactly one root in common then
Answer» If $x^{2} - 1 = - b^{2} - 2 b x a n d x^{2} - 1 = - a^{2} - 2 a x$ have exactly one root in common then

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